3[n+2(11-n)]=48

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Solution for 3[n+2(11-n)]=48 equation:


Simplifying
3[n + 2(11 + -1n)] = 48
3[n + (11 * 2 + -1n * 2)] = 48
3[n + (22 + -2n)] = 48

Reorder the terms:
3[22 + n + -2n] = 48

Combine like terms: n + -2n = -1n
3[22 + -1n] = 48
[22 * 3 + -1n * 3] = 48
[66 + -3n] = 48

Solving
66 + -3n = 48

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-66' to each side of the equation.
66 + -66 + -3n = 48 + -66

Combine like terms: 66 + -66 = 0
0 + -3n = 48 + -66
-3n = 48 + -66

Combine like terms: 48 + -66 = -18
-3n = -18

Divide each side by '-3'.
n = 6

Simplifying
n = 6

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